Foxholer
Blackballed
I believe you have things somewhat Ar..about face! Forget that 5.381 and simply use CH (cf CR) = HI*Slope/113. Though the results will be the same (1 shot for every 5.381 of Slope over 113)!Slope Rating calculation is :
Bogey Rating minus Course Rating multiplied by 5.381.
So the bigger the difference between the Bogey Player and the Scratch Player, the higher the Slope Rating.
Par is irrelevant in the calculation, even if the Course Rating (scratch player) is assessed as higher than Par.
Here are two examples :
Course 1 Par of 71 has BR 95.4 - CR 72.7 = 22.7 * 5.381 = 122.1 (122)
Course 2 Par of 72 has BR 98.3 - CR 72 = 26.3 * 5.381 = 141.5 (142)
At course 1 the scratch player cannot break par but at course 2 he can play to par.
But because the 20ish* handicapper has a tougher time at course 2, relative to the scratch player, the slope rating is higher.
*If 113 is the ’norm’, shouldn’t the bogey player be described as a 21 handicapper (113 / 5.381 = 20.99)?
113 is the Slope value where a 'Bogey' player and the Scratch player are 'expected' to play to their Handicap Indices (0 and 20-ish. On any course with a Slope rating above 113, the Bogey player is 'expected' to find it tougher to play to their HI - so needs the Slope/113 extra shots!
And, from memory, 'Bogey Player' is described as someone in the range of 17-21, so some (statistical?) leeway.
Remember that Golf scores, therefore handicapping - at least at higher handicap levels, has to use some pretty inconsistent 'input data'! So/And your statement that 'the Scratch player cannot break Par' is twaddle! But, on average, (s)he's not expected to!
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