Who's man enough?????

Smiffy

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someone mind posting what the final teams are... I've read thru the thread and come up with 8 at the club and 10 at the pub :confused:

club team

smiffy
leftie
justone
dhan
full throttle
lig
rosecott
ray taylor

pub team

virtuocity
sandmagnet
greg lindley
midnight
whereditgo
norman porritt
ewan porritt
chrisd
 

JustOne

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I have worked out the 'matches', we are apparently playing individual stableford across the entire 4 rounds so as such they are not 'matches' but I'm sure most games will have a little wager :thup:

Hopefully no one is playing with the same partner more than once or the same opposition more than twice.... if there's any glaring mistakes (you're with the same partner/oppo 3 times) please point it out as I have suddenly gone NAME BLIND!! :mad:


ROUND 1
smiffy justone virtuocity sandmagnet
leftie lig whereditgo norman porritt
dhan full throttle midnight greg lindley
rosecott ray taylor chrisd ewan porritt

ROUND 2
smiffy dhan whereditgo ewan porritt
leftie ray taylor virtuocity chrisd
justone full throttle midnight norman porritt
lig rosecott sandmagnet greg lindley

ROUND 3
smiffy rosecott ewan porritt midnight
leftie full throttle sandmagnet norman porritt
justone ray taylor whereditgo chrisd
dhan lig virtuocity greg lindley

ROUND 4
smiffy leftie midnight chrisd
justone lig virtuocity ewan porritt
dhan rosecott sandmagnet whereditgo
full throttle ray taylor norman porritt greg lindley
 

chrisd

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I'm really sorry but I've got a real problem for my team!




I shot 41 points in today's Stableford - I'm gonna get a cut!!


Sorry boys!
 

rosecott

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I have worked out the 'matches', we are apparently playing individual stableford across the entire 4 rounds so as such they are not 'matches' but I'm sure most games will have a little wager :thup:

Hopefully no one is playing with the same partner more than once or the same opposition more than twice.... if there's any glaring mistakes (you're with the same partner/oppo 3 times) please point it out as I have suddenly gone NAME BLIND!! :mad:


ROUND 1
smiffy justone virtuocity sandmagnet
leftie lig whereditgo norman porritt
dhan full throttle midnight greg lindley
rosecott ray taylor chrisd ewan porritt

ROUND 2
smiffy dhan whereditgo ewan porritt
leftie ray taylor virtuocity chrisd
justone full throttle midnight norman porritt
lig rosecott sandmagnet greg lindley

ROUND 3
smiffy rosecott ewan porritt midnight
leftie full throttle sandmagnet norman porritt
justone ray taylor whereditgo chrisd
dhan lig virtuocity greg lindley

ROUND 4
smiffy leftie midnight chrisd
justone lig virtuocity ewan porritt
dhan rosecott sandmagnet whereditgo
full throttle ray taylor norman porritt greg lindley

For the last 5 years I have been trying to arrange 12 players over 4 rounds with everyone playing with the other 11 players. It is impossible. I propose a £5 per player contribution prize for anyone who comes up with a solution better than JustOne's.
 

JustOne

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swap norman and ewan round in round 3 and it's fine,

It would appear that I'm playing Ray Taylor on 3 occasions

Thanks guys BUT ALSO I haven't accounted for the fact that Smiffy and Ray are sharing a buggy on day one (so will play together) and some people have said that they want to walk BOTH ROUNDS on day 2 so that means all the buggies/pairings need to be worked out for whom is playing who so no one ends up alone with a buggy to themselves :confused: ...... so on that bombshell I'm just going to leave it for someone else to sort out. :thup:
 

LIG

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For the last 5 years I have been trying to arrange 12 players over 4 rounds with everyone playing with the other 11 players. It is impossible. I propose a £5 per player contribution prize for anyone who comes up with a solution better than JustOne's.

Thanks guys BUT ALSO I haven't accounted for the fact that Smiffy and Ray are sharing a buggy on day one (so will play together) and some people have said that they want to walk BOTH ROUNDS on day 2 so that means all the buggies/pairings need to be worked out for whom is playing who so no one ends up alone with a buggy to themselves :confused: ...... so on that bombshell I'm just going to leave it for someone else to sort out. :thup:

I have a spreadsheet that I did for a team event some time ago that might be suitable. Iirc, there were only a few peeps playing with the same person more than once. Can't remember if it was for teams of 12 or 8 - will dig it out later.

Edit: it is later - I've found it. 8-a-side so:whoo:
 
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Smiffy

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For the last 5 years I have been trying to arrange 12 players over 4 rounds with everyone playing with the other 11 players. It is impossible. I propose a £5 per player contribution prize for anyone who comes up with a solution better than JustOne's.

I think the best way to sort it out is to rely on the "luck of the draw"
With 16 people playing it is going to be impossible to play with EVERYBODY so what I suggest is put all of the cards into a hat, mix them up and just pull 4 out for each group.
Because we are no longer playing matchplay, it doesn't really matter if you get four guys from the flats or pub playing together to be honest. That's the luck of the draw.
Okay, if somebody comes out of the hat playing with the same person three times on the trot, we can then mix it up a bit between ourselves, let's just see how it pans out.
That way there can be no accusations of group "fixing" etc.
Just to let you know I have booked...

3 buggies for Sunday (18 holes)
6 buggies for Monday (36 holes)
3 buggies for Tuesday (18 holes)
 

rosecott

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I think the best way to sort it out is to rely on the "luck of the draw"
With 16 people playing it is going to be impossible to play with EVERYBODY so what I suggest is put all of the cards into a hat, mix them up and just pull 4 out for each group.
Because we are no longer playing matchplay, it doesn't really matter if you get four guys from the flats or pub playing together to be honest. That's the luck of the draw.
Okay, if somebody comes out of the hat playing with the same person three times on the trot, we can then mix it up a bit between ourselves, let's just see how it pans out.
That way there can be no accusations of group "fixing" etc.
Just to let you know I have booked...

3 buggies for Sunday (18 holes)
6 buggies for Monday (36 holes)
3 buggies for Tuesday (18 holes)

That way lies chaos. I suggest we stick with JustOne's draw as he has taken buggy partners into account.
 

rosecott

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No he hasn't!!
I was supposed to be sharing a buggy with Ray for round 1.
I'm not even playing with Ray over the course of the 4 rounds!!

OK - just tell LIG who will be having buggies each round and he can sort it. BTW that JustOne is useless.
 
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