Handicaps in Match Play

MARKB

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I've played a number of 27 hole golf courses where they consist of 3 nine hole courses. Many have handcaps based on whether each of the nine holes are played as the front or back of an 18 hole round. However, yesterday I played at a golf club where each of the 3 nine hole courses had a handicap HCP rating of just 1 to 9. I was playing match play and had to give 13 shots to my opponent. What is the correct procedure to working out which holes the opponent receives a shot? Is it in this scenario holes with HCP rating 1 to 6 then on which of the nine does one allocate the extra shot using the HCP rating 7? Or does the opponent receive a shot on every hole as the card has been written only with HCP ratings of 1 to 9, in which case they have the advantage of receiving 18 not 13 shots?
 
For one of the nines double the indexes so they're even. Typically the longer/harder nine will be the odds so my guess would be to double the indexes of the shorter nine and go from there.

If your opponent is a member surely they will have a procedure they use in their internal comps.
 
I don't see how that works.

Course A Indices 1, 2 ,3 ....9

Course B Indices 1, 2, 3 ....9

Double A indices 2, 4, 6 .... 18

Two holes with Index 2 ?


You could add to one course so A (say) would be 10, 11, 12 .... 19
But that would mean all the high are on one 9 and the low on the other.


But it should be somewhere on the card(s) or in the pro-shop.
 
Unless we've been specifically told different by the pro or marked on the card we've always used

Front nine - double the SI and subtract 1
Back nine - double the SI.

That way it's spread out with odds on the front and evens on the back.
 
I don't see how that works.

Course A Indices 1, 2 ,3 ....9

Course B Indices 1, 2, 3 ....9

Double A indices 2, 4, 6 .... 18

Two holes with Index 2 ?


You could add to one course so A (say) would be 10, 11, 12 .... 19
But that would mean all the high are on one 9 and the low on the other.


But it should be somewhere on the card(s) or in the pro-shop.

It use to work just fine and simple when the odd S.I numbers were on one 9 and the even numbers on the other, but that was far too simple wasn't it , so they changed it .:D
 
Complete brain fart admittedly, the club should have a procedure in place. Where was it out of interest?

Suppose the correct way to express it is think of one of nines as the odd nine and one as the even, then convert one lot of 1-9 into 1,3,5,7,9,11,13,15,17 in their respective order and the other lot into 2,4,6,8,10,12,14,16,18 again in the order where they rank 1-9 on the card.
 
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