Who wins this hole?

[stevelev]

This is for those who fully understand scoring for pairs matchplay. Handicaps as far as I know where 3/4's

If there are 2 pairs playing in a match:
Pair 1, Player A 4HCAP, Player B 9HCAP
Pair 2, Player C 16HCAP, Player D 20HCAP

Hole 1: (Par 4 Score Index 3)
Player A 6
Player B 5
Player C 7
Player D 5

Which pair win the hole.

Also how are scores calculated on each hole relative to the score index.

 

[Foxholer]

Players B and D halved it.

(Traditional) Matchplay rules are that lowest handicap gets no strokes anywhere and others get 3/4 of difference from him/her.

So B gets 4 shots; c gets 9 and D gets 12. - with shoys on those Stroke Indexed holes.

3 get strokes, with the 2 5s halving it.

 

[upsidedown]

Hole halved by B and D with nett 4's

 

[Bratty]

I think this is right:
Player A as lowest has no shots and everyone else gets 3/4 the difference if them. So B gets 4, C gets 9 and D gets 12.

So, with those as the now fixed handicaps, player D now only gets one shot on index 3, therefore the hole is halved.

Assuming this was a fourball betterball match, that's how I see it.

Or have I missed something?

 

[duncan mackie]

B & D halve the hole in 5 nett 4's.

Strokes are taken against A as the low handicapper on the basis of 3/4 of the difference (4,9 & 12 in this case) according to the SI of the holes ie on SI 1-4 everyone deducts 1 from their score v A

Edit - I can't handle small phone screens and keyboards fast enough around here!

 

[rosecott]

Player B receives a stroke on SIs 1-4
Player C receives a stroke on SIs 1-9
Player D receives a stroke on SIs 1-12

 

[pbrown7582]

Players B and D halved it.

(Traditional) Matchplay rules are that lowest handicap gets no strokes anywhere and others get 3/4 of difference from him/her.

So B gets 4 shots; c gets 9 and D gets 12. - with shoys on those Stroke Indexed holes.

3 get strokes, with the 2 5s halving it.

Hole halved by B and D with nett 4's

Fairly straight forward what's the punch line?

 

[Bratty]

B & D halve the hole in 5 nett 4's.

Strokes are taken against A as the low handicapper on the basis of 3/4 of the difference (4,9 & 12 in this case) according to the SI of the holes ie on SI 1-4 everyone deducts 1 from their score v A

Edit - I can't handle small phone screens and keyboards fast enough around here!

I thought exactly the same thing, Duncan!

 

[stevelev]

So what is the handicaps are the following Rosecott
Player A 8
Player B 9
Player C 16
Player D 20

Cheers

 

[Bratty]

All you need to do is take the difference of each player's handicap from the lowest player. Then divide each by 3/4.
B gets 1 shot, C gets 6 and D gets 9.

 

[duncan mackie]

So what is the handicaps are the following Rosecott
Player A 8
Player B 9
Player C 16
Player D 20

Cheers

Blank/ 1 6 9

 

[Bratty]

Blank/ 1 6 9

Fastest finger first, Duncan! :rofl:

 

[pbrown7582]

So what is the handicaps are the following Rosecott
Player A 8
Player B 9
Player C 16
Player D 20

Cheers

Shots off player a
Player b 1
C 6
D 8

 

[rosecott]

Shots off player a
Player b 1
C 6
D 8

Don't combine drink and arithmetic on Saturday evening.

 

[pbrown7582]

Don't combine drink and arithmetic on Saturday evening.

:rofl:



Worth a try you know what cheats and bandits these 20 h/caps are.

 

[Foxholer]

All you need to do is take the difference of each player's handicap from the lowest player. Then divide each by 3/4.
B gets 1 shot, C gets 6 and D gets 9.

[Pedant Mode]

It's actually 'multiply' each by 3/4s

[/Pedant Mode]

'Take 3/4s of' works though. And we knew what you meant!

 

[Bratty]

[Pedant Mode]

It's actually 'multiply' each by 3/4s

[/Pedant Mode]

'Take 3/4s of' works though. And we knew what you meant!

Well caught, sir! I was trying to beat Duncan to the punch!

 

[SwingsitlikeHogan]

And the tricky bit of this question and/or punchline. Or am I missing something.

 

[rosecott]

And the tricky bit of this question and/or punchline. Or am I missing something.

No sir, nothing to see here, just move on.